Given the circuit shown for which R1 3.9 Mo, R2 2.4 Mo, R3 6.3 Mo, R4 8.7 MW S1

Question

Given the circuit shown for which R1 3.9 Mo, R2 2.4 Mo, R3 6.3 Mo, R4 8.7 MW S1 MQ, C-6.8 HF,and E 26.0V. For charging, we open S2 and close S1. For R2 R1 discharge, after a full charge, we open S1 then close S2. a) What is the charge time constant for the circuit? Answer in units of seconds. R3 106.5 SUBMIT b) What is the discharge time constant for the circuit? Answer in units of seconds. S2 R4 SUBMIT After fully discharging the circuit, we close S2 and then close S1. The capacitor will charge. c) What is in micro-amps the current through R2 once the capacitor is fully charged? SUBMIT d) What is in micro-amps the current through R3 once the capacitor is fully charged? SUBMIT e) What is in volts, the voltage across the capacitor once it is fully charged? SUBMIT

Explanation / Answer

a)

s1 is closed , s2 is open

Total resistance of the circuit = R1 + R2 + R4 = 3.9 + 2.4 + 8.7 = 15 Mohm = 15 x 106 ohm

Capacitance = C = 6.8 uF = 6.8 x 10-6 F

Time constant = T = RC = (15 x 106 ) ( 6.8 x 10-6 ) = 102 sec

B)

s1 is open , s2 is closed

Total resistance of the circuit = R2 + R3 = 2.4 + 6.3 = 8.7 Mohm = 8.7 x 106 ohm

Capacitance = C = 6.8 uF = 6.8 x 10-6 F

Time constant = T = RC = (8.7 x 106 ) ( 6.8 x 10-6 ) = 59.16 sec

C)

when C is fully charged , that branch will behave as open circuit and no current will flow through R2

D)

total resistance = R1 + R3 + R4 = 3.9 + 6.3 + 8.7 = 18.9

Current = Voltage/resistance = 26 / (18.9 x 106) = 1.38 uA

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