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In a rectangular coordinate system, a positive point charge q = 9.00 nC is place

ID: 1396963 • Letter: I

Question

In a rectangular coordinate system, a positive point charge q = 9.00 nC is placed at the point x=0.240 m , y=0, and an identical point charge is placed at x= -0.240 m , y=0. Find the x and ycomponents and the magnitude and direction of the electric field at the following points.

Part A

Find the x and y components and the magnitude of the electric field at the origin.

Part B

Part C

Find the x and y components and the magnitude and direction of the electric field at x= 0.480 m , y=0.

Part D

Part E

Explanation / Answer


A) Since the direction of Elecric filed from positive charge is away from the charge .Hence Ex = 0 N/C

Ey = 0 N/C

C) Ex = E1+E2

E1 = k*q/r1^2 = (9*10^9*9*10^-9)/(0.48+0.24)^2 = 159.25 N/C

E2 = (9*10^9*9*10^-9)/(0.24)^2 = 1406.25 N/C

Ex = 159.25+1406.25 = 1565.5 N/C

Ey = 0 N/C

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