In a rectangular coordinate system, a positive point charge q = 9.00 nC is place
ID: 1396963 • Letter: I
Question
In a rectangular coordinate system, a positive point charge q = 9.00 nC is placed at the point x=0.240 m , y=0, and an identical point charge is placed at x= -0.240 m , y=0. Find the x and ycomponents and the magnitude and direction of the electric field at the following points.
Part A
Find the x and y components and the magnitude of the electric field at the origin.
Part B
Part C
Find the x and y components and the magnitude and direction of the electric field at x= 0.480 m , y=0.
Part D
Part E
Explanation / Answer
A) Since the direction of Elecric filed from positive charge is away from the charge .Hence Ex = 0 N/C
Ey = 0 N/C
C) Ex = E1+E2
E1 = k*q/r1^2 = (9*10^9*9*10^-9)/(0.48+0.24)^2 = 159.25 N/C
E2 = (9*10^9*9*10^-9)/(0.24)^2 = 1406.25 N/C
Ex = 159.25+1406.25 = 1565.5 N/C
Ey = 0 N/C
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