In a rectangular coordinate system, a positive point charge q1 = +7.50 nC is pla

Question

In a rectangular coordinate system, a positive point charge q1 = +7.50 nC is placed at the point 0.250 m, y=0, and an identical point charge q2 (+7.5 nC) is placed at x= - 0.250 m, y = 0. Find the x and y components and the magnitude and direction of the electric field at the following points. Find the X and Y components, the magnitude, and the direction of the electric field at x= 0.250 m, y= - 0.350 m. I have tried to solve this question multiple ways and am still unable to come out with the correct answer. Since both original charges are on the X-axis, and the 3rd charge is below the X-axis, I solved for the hypotensuse connecting q2 to q3. I then solved for the resulting x and y components but my answers were counted incorrect. I will award tons of karma points to whoever is able to provide me an explanation on how to answer and approach this problem (step by step). I really want to understand this concept, so I genuinely appreciate any and all help you can provide!!! Thank you in advance!

Explanation / Answer

well this is easy if u solve by taking components
electric field because of charge q1 = 1/40 7.5/(.350)2j : note that this electric field is along y axis and it does not contribute horizontally

q2 : 1/40 7.5 { 1/.52i +1/.3502 j }this contributes to electric field along x and y

so net electric field = 1/40 *7.5{1/.25i +2/.1225j}

problem solved ...it is now not a big deal to calculate elctric field

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