ONLY NEED PART F,G& H In a rectangular coordinate system, a positive point charg

Question

ONLY NEED PART F,G& H

In a rectangular coordinate system, a positive point charge q = 9.00 nC is placed at the point x=0.240 m , y=0, and an identical point charge is placed at x= -0.240 m , y=0. Find the x and ycomponents and the magnitude and direction of the electric field at the following points.

Part A

Find the x and y components and the magnitude of the electric field at the origin.

Part B

Part C

Find the x and y components and the magnitude and direction of the electric field at x= 0.480 m , y=0.

Part D

E = ______ N/C

Part E

=_______ from the +x axis

Part F

Find the x and y components and the magnitude and direction of the electric field at x= 0.240 m , y= -0.350 m .

Ex,Ey = _______ N/C

Part G

E =______N/C

Part H

= _____ from the +x axis

Explanation / Answer

F)
let q1 is the charge placed on +x axis

q2 is the charge placed on -x axis

E1 = k*q1/y^2

= 9*10^9*9*10^-9/0.35^2

= 661 N/c

E1x = 0

E1y = -661 N/c

E2 = k*q2/r^2

= 9*10^9*9*10^-9/(0.48^2 + 0.35^2)

= 229.5 N/c

E2x = E2*cos(theta)

= 229.5*0.48/sqrt(0.48^2+0.35^2)

= 185.4 N/c

E2y = -E2*sin(theta)

= -229.5*0.35/sqrt(0.48^2+0.35^2)

= -135.2 N/c

Ex = E1x + E2x = 0 + 185.4 = 185.4 N/c

Ey = E1y + E2y = -661 - 135.2 = -796.2 N/c

G)

E = sqrt(Ex^2 + Ey^2)

= 817.5 N/c

F) theta = tan^-1(Ey/Ex)

= tan^-1(796.2/185.4)

= 77 dgrees below +x axis

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