1) find the current in each resistor. 2) find the voltage across each resistor.

Question

1) find the current in each resistor.
2) find the voltage across each resistor.
3) find the power dissipated in each resistor.
4) which resistor dissipates the most power, the one with greatest resistance or the one with the least resistance? Explain why this should be. 54.SB2015 Problem 19.51 Cha ter 19Problem 19.51 Problem 19.51 R1 = 1.73 Three resistors having resistances of , R2 = 2.45 and R3 = 4.95 respectively. are connected in series to a 28.5 V battery that has negligible internal resistance | has negligible internal resistance

Explanation / Answer

1) Rnet = R1 + R2 + R3

= 1.73 + 2.45 + 4.95

= 9.13 ohms

current in each resistor, I = V/Rnet

= 28.5/9.13

= 3.12 A

2) V1 = I*R1 = 3.12*1.73 = 5.4 V

V2 = I*R2 = 3.12*2.45 = 7.65 V

V3 = 3.12*4.95 = 15.45 V

3)

P1 = I^2*R1 = 3.12^2*1.73 = 16.85 W

P2 = I^2*R2 = 3.12^2*2.45 = 23.85 W

P3 = I^2*R3 = 3.12^2*4.95 = 48.2 W

4) here current is same in all the resistors.

so, the one which has greter resistance will dissipate most power.

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