Two 3.00 cm × 3.00 cm plates that form a parallel-plate capacitor are charged to
ID: 1397630 • Letter: T
Question
Two 3.00 cm × 3.00 cm plates that form a parallel-plate capacitor are charged to± 0.708 nC
A) What is the electric field strength inside the capacitor if the spacing between the plates is 1.30 mm ?
Express your answer with the appropriate units.
B)
What is potential difference across the capacitor if the spacing between the plates is 1.30 mm ?
Express your answer with the appropriate units.
C)
What is the electric field strength inside the capacitor if the spacing between the plates is 2.60 mm ?
Express your answer with the appropriate units.
D)
What is the potential difference across the capacitor if the spacing between the plates is 2.60 mm ?
Express your answer with the appropriate units.
Explanation / Answer
A) E = Q/(A*epsilon)
= 0.708*10^-9/(0.03^2*8.854*10^-12)
= 88849 N/c
B) V = E*d
= 88849*1.3*10^-3
= 115.5 volts
C) E does not depned on distance btween plates.
E = 88849 N/c
D) V = E*d
= 88849*2.6*10^-3
= 231 volts
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