Two 3.00 cm x 3.00 cm plates that form a parallel plate capacitor are charged to

Question

Two 3.00 cm x 3.00 cm plates that form a parallel plate capacitor are charged to +/- 0.708 nC.

A. What is the electric field strength inside the capacitor if the spacing between the plates is 1.50 mm?

E= ___ V/m

B. What is the potential difference across the capacitor if the spacing between the plates is 1.50 mm ?

V= ____V

C. What is the electric field strength inside the capacitor if the spacing between the plates is 3.00 mm?

V=____ V/m

D. What is the potential difference across the capacitor if the spacing between the plates is 3.00 mm?

V= ____V

Explanation / Answer

charge density=Q/A=0.708*10^-9/0.03^2=7.8667*10^-7 C/m^2

a)

E=charge density/epsilon=7.8667*10^-7/(8.85*10^-12)=88888.89V/m

b)

V=Ed=133.33V

c)E=charge density/epsilon=7.8667*10^-7/(8.85*10^-12)=88888.89V/m

d)

V=Ed=266.67V

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