Two pucks are placed on a frictionless table as shown above. Each puck has mass

Question

Two pucks are placed on a frictionless table as shown above. Each puck has mass m. A positive charge of +2q0 is placed on the left charge and a charge of +3q0 is placed on the right puck. The pucks are released at rest and the distance D between the two pucks. (a) For each puck, what is the magnitude and direction of the electric force at the instant just after they are released? (b) For each puck, what is the magnitude and direction of the acceleration at the instant just after they are released? (c) If m = 0.800 kg and d = 5.333 meters, what is the value of q0 that would yield an acceleration of the right pucks of 2.000 Gees

Explanation / Answer

given,

mass of the puck = m

charge on the left puck = 2q0

charge on the right puck = 3q0

distance between the puck = D

electric force on the puck = k * q1 * q2 / d^2

where k is a constant with value = 9 * 10^9

putting the values

electric force on the puck = k * 2q0 * 3q0 / D^2

electric force on the puck = k * 6q0^2 / D^2

force = mass * acceleration

k * 6q0^2 / D^2 = m * acceleration

acceleration = k * 6q0^2 / (D^2 * m)

acceleration at the instant just after they are released = k * 6q0^2 / (D^2 * m)

if,

m = 0.8 kg

d= 5.33 m

acceleration = 2g

putting the values in the equation

acceleration = k * 6q0^2 / (D^2 * m)

2 * 9.8 = 9 * 10^9 * 6 * q0^2 / (5.333^2 * 0.8)

q0 = 9.09 * 10^-5 C

value of q0 = 9.09 * 10^-5 C

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