Problem 20.38 A solenoid having 180 turns and a cross-sectional area of 6.76 cm^

Question

Problem 20.38 A solenoid having 180 turns and a cross-sectional area of 6.76 cm^2 carries a current of 1.14 A Part A If it is placed in a uniform 116 T magnetic field, find the torque this field exerts on the solenoid if its axis is oriented perpendicular to the field. Part B If it is placed in a uniform 116 T magnetic field, find the torque this field exerts on the solenoid if its axis is oriented parallel to the field. Part C If it is placed in a uniform 1.16 T magnetic field, find the torque this field exerts on the solenoid if its axis is oriented at 30.0 degree with the field.

Explanation / Answer

torque = t = NBIAsintheta

here given

N = 180

B = 1.16 T

I = 1.14 A

A = 6.76 cm^2 = 6.76 x 10^-4 m^2

part a ) perpendicular to the axis theta = 90 degree

t = 180 x 1.14 x 1.16 x 6.76 x 10^-4 x sin90

t = 0.161 N.m

part b ) theta = 0

sin0 = 0

t = 0

part c ) theta = 30

t = 180 x 1.14 x 1.16 x 6.76 x 10^-4 x sin30

t = 0.08045 N.m

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