In a particular molecular electric dipole, point charges ± 3.20×10 19 C are effe

Question

In a particular molecular electric dipole, point charges

± 3.20×1019 C are effectively separated by a small fraction of a nanometer.

Part A

If the separation distance is 7.70×102 nm , find the magnitude of the electric dipole moment for this particular molecular dipole.

Express your answer in coulomb meters to three significant figures.

Part B

When such a dipole is in an external electric field, it is generally a good approximation to assume that the electric field is uniform. Such an assumption is usually valid simply because the dipole is so tiny that the electric field generally cannot change by very much over the separation distance of the two charges. Assume that the charges are in a uniform electric field whose direction makes an angle of 37.5 degrees with the dipole moment vector. What is the magnitude of this field if the torque exerted on the dipole has magnitude 9.50×1024 Nm ?

Express your answer in newtons per coulomb to three significant figures.

Explanation / Answer

A) dipole moment, P = q*L (here q is magnitude of charge and L is the distance between the two charges)

= 3.2*10^-19*7.7*10^-2*10^-9

= 2.464*10^-29 C.m

B) Apply, Torque on dipole, T = P*E*sin(theta)

==> E = T/(P*sin(theta))

= 9.5*10^-24/(2.464*10^-29*sin(37.5))

= 6.333*10^5 N/c

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