6. 0/4 points | Previous Answers SerPSE9 23.P.016. My Notes Ask Your Teacher Two

Question

6. 0/4 points | Previous Answers SerPSE9 23.P.016. My Notes Ask Your Teacher Two small metallic spheres, each of mass m = 0.180 g, are suspended as pendulums by light strings of length L as shown in the figure below. The spheres are given the same electric charge of 8.0 nC and they come to equilibrium when each string is at an angle of 5.10 with the vertical. How long are the strings? 0.020 Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. m Need Help? Roadlt Need Help? El Roadlt

Explanation / Answer

let the length of string is L ,

the tension in the string is T ,

distance between charges , d = 2*L*sin(5.10)

d = 0.178 *L

Now, for the charge to be in equilibrium ,

T*sin(5.1) = F

T*cos(5.1) = m*g

>> F/m*g = tan(5.1)

k*q^2/d^2 = m*g*tan(5.1)

9*10^9 * ( 8 *10^-9)^2/(0.178 * L)^2 = 0.180 *10^-3 * 9.8 * tan(5.1)

solving for L

L = 0.34 m

the length of rod is 0.34 m

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