If the speed of the car at height y 3 is 17.3 m/s, how much mechanical energy is

ID: 1398569 • Letter: I

Question

If the speed of the car at height y3 is 17.3 m/s, how much mechanical energy is lost (due to frictional forces) as the car travels from y1 to y3? HINT: Compare the total mechanical energy at the two heights.
Enter a positive value for the amount of energy lost. THREE significant figures are required.

A roller coaster car of mass 2330 kg is at the top of a track. The heights indicated in the drawing are: y1 = 24.0 m, y2 = 7.00 m, y3 = 2.90 m. (The drawing is not to scale.) When the car is at the height y1, it has a speed of 0.600 m/s.

Explanation / Answer

Here ,

at the height y1

initial mechannical energy , E1 = 0.5 ( mv^2 ) + m*gh

E1 = 0.5 * 2330 * 0.60^2 + 2330 * 9.8 * 24

E1 = 548435 J

Now , at the height y3 ,

final mechanical energy , E3 = 0.5 ( mv^2 ) + m*gh

E3 = 0.5 * 2330 * 17.3^2 + 2330 * 9.8 * 2.90

E3 = 414891 J

loss in mechanical energy = E1 - E3

loss in mechanical energy = 548435 - 414891

loss in mechanical energy = 133543 J

the loss in mechanical energy of the cart is 133543 J

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If the speed of the car at height y 3 is 17.3 m/s, how much mechanical energy is

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