please help ASAP! Last attempt Two 10-cm-diameter charged rings face each other,

Question

please help ASAP! Last attempt

Two 10-cm-diameter charged rings face each other, 29 cm apart. The left ring is charged to -27 nC and the right ring is charged to +27 nC .

Part A

What is the magnitude of the electric field E  at the midpoint between the two rings?

Express your answer to two significant figures and include the appropriate units.

Part B

What is the direction of the electric field E  at the midpoint between the two rings?

Part C

What is the magnitude of the force F  on a -1.0 nC charge placed at the midpoint?

Express your answer to two significant figures and include the appropriate units.

Part D

What is the direction of the force F  on a -1.0 nC charge placed at the midpoint?

Explanation / Answer

here,

diameter of the ring , d = 10 cm

radius of the ring , r = 5 cm

r = 0.05 m

distance of the mid point from the centre of the ring , a = 29/2

x = 0.145 m

charge Q1 = -27 nC

Q1 = -27*10^-9 C

charge Q2 = -27 nC

Q2 = 27*10^-9 C

for the ring charge , the electic field on the axis is

E = K*Qx/(x^2 + a^2)^1.5

the electric feild at the mid point is

Enet = E2 - E1

Enet = K*Q2x/(x^2 + a^2)^1.5 - K*Q1x/(x^2 + a^2)^1.5

Enet = 9* 10^9 *27*10^-9*0.145 /(0.145^2 + 0.05^2)^1.5 + 9* 10^9 *27*10^-9*0.145 /(0.145^2 + 0.05^2)^1.5

Enet = 19530.34 N/C

the magnitude of the electric field E at the midpoint between the two rings is 19530.34 N/C

part B)

the direction of the electric field E at the midpoint between the two rings is b)to the left ring

part C)

charge at mid point is q = - 1 nC

q = - 1 * 10^-9 C

for the ring charge , the force on the axis is

Fnet = Enet * q

Fnet = - 19530.34 * 10^-9

Fnet = 1.95 * 10^-5 N

the magnitude of the net force is 1.95 * 10^-5 N

part D)

the direction of the force F on a -1.0 nC charge placed at the midpoint is c)To the right ring.

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