Question
please help
According to Experian, as of December 2011, the average credit store for people living in Missouri was 690. Suppose credit scores are normally distributed and suppose the standard deviation was 50. If one randomly selected person's credit falls in the bottom 33% of all Missourians at most what was their score? (Assume credit scores can have decimals for this problem) a. 712 b. 668 c. 706.5 d. 673.5 e. 708.535 f. 671.465 Suppose that there are an average of 6 flaws in 15 yards of fabric. What is the probability that you will find your first flaw within 2 yards? e^-3 = -0067 e^-1.25 = 2865 e^-0.5 = 6065 e^-3.2 = 0408 e^-1.2 = 2012 e^-0.4 = 6703 e^-2.3 = 0821 e^-2 = e^0.25 = 7788
Explanation / Answer
7. For a bottom 33%, z = -0.44
Hence,
Credit score
= 690 - 0.44*50
= 668
Option b is correct.
