A circular coil 14.0 cm in diameter and containing nine loops lies flat on the g

Question

A circular coil 14.0 cm in diameter and containing nine loops lies flat on the ground. The Earth's magnetic field at this location has magnitude 4.50×105T and points into the Earth at an angle of 58.0 below a line pointing due north. A7.80-A clockwise current passes through the coil.

Part A

Determine the torque on the coil.

Express your answer using three significant figures and include the appropriate units.

Part B

Which edge of the coil rises up: north, east, south, or west?

Which edge of the coil rises up: north, east, south, or west?

Explanation / Answer

given,

diameter of the coil = 14 cm

earth's magnetic field = 4.50×10^5 T

dip angle = 58 degree

current = 7.8 A

number of loops = 9

Torque = number of loops * current * magnetic field * area * cos(58)

Torque = 9 * 7.8 * 4.50 * 10^5 * pi * 0.14^2 * cos(58)

Torque = 0.000103 Nm

south

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