a 2[C] point charge \"A\" is held at the origin ( x =0, y =0) while point charge

Question

a 2[C] point charge "A" is held at the origin (x=0,y=0) while point charge "B" (3[C]) is moved from x=0.10[m]
to x=0.40[m],y=0.30[m].
. . . a) calculate the electric Potential due to "A" , at B's starting location.
. . . b) calculate V caused by A, at B's ending location
. . . c) calculate the voltage at the ending place, relative to the starting place
. . . d) calculate the change in B's electric Potential Energy . . . . did B require outside Energy as it moved, or releaseEnergy as it was moved?

Explanation / Answer

a)

Potential at starting position,

Vb = kQ/r

So, Vb = 9*10^9*(2*10^-6)/(0.1) = 1.8*10^5 V/m

b)

Vb' = kQ/r = 9*10^9*(2*10^-6)/sqrt(0.4^2+0.3^2) = 3.6*10^4 V/m

c)

Vb - Vb' = (18 - 3.6)*10^4 V/m = 1.44*10^5 V/m

d)

change in energy = 1.44*10^5*3*10^-6 = 0.432 J

Energy is required as the sign is positive

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