PLEASE EXPLAIN! I looked up a similar answer on Chegg and it didn\'t make any se
ID: 1399639 • Letter: P
Question
PLEASE EXPLAIN! I looked up a similar answer on Chegg and it didn't make any sense for part b or c. Thanks.
A Cavendish apparatus is shown in in the figure below. You can estimate the angle of rotation of the rod in the following way. Assume that the rod is massless, that there is no resistance to rotation, and that the same force acts on both masses. Then the acceleration of each mass may be computed independently, using Newton's second law. Furthermore, if the distance each mass moves is small compared with the separation between m and M, then the acceleration can be treated as constant. (Take m = 52.4 g and M = 1.83 kg.)
(a) Find the acceleration of each mass.
(b) How long a time is required for each mass to move a distance of 1 mm?
(c) Through what angle does the rod rotate during this interval?
Explanation / Answer
As
F = G m M / r^2
and r = 0.05 m, then
F = 2.558E-6 N
Thus, the acceleration of each is
a1 = F / m = 1.398*10^-6 m/s^2
a2 = F / M = 4.882*10^-8 m/s^2 [ANSWERS, A]
***********************
As
d = vo t + 1/2 a t^2
and vo = 0 for both, then
t = sqrt(2a / d)
As d = 0.001 m, then
t1 = 0.05288 s
t2 = 0.009881 s [ANSWERS, B]
************************
As
theta = d / r
and r = 0.06 m, then
theta = 0.01666 rad or 0.9549 degrees [ANSWER, C]
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