HELP. I TRIED A COUPLE OF TIMES AND GOT 5950.41W AND 4958.7W. None of them were

Question

HELP. I TRIED A COUPLE OF TIMES AND GOT 5950.41W AND 4958.7W. None of them were correct.

The rate of heat conduction out of a window on a winter day is rapid enough to chill the air next to it. To see just how rapidly windows conduct heat, calculate the rate of conduction in watts through a 2.50 m2 window that is 0.605 cm thick if the temperatures of the inner and outer surfaces are 5.00°C and -10.0°C, respectively. This rapid rate will not be maintained - the inner surface will cool, and frost may even form.

Explanation / Answer

given,

area A=2.5 m^2

temparature difference dT=T2-T1 =5-(-10) =15 oC

the rate of heat transfer is,

Q/t= K*A(T2-T1)/d

here,

k is co efficent of thermal conductivity

now,

q/t=k*2.5*(5-(-10))/(0.605*10^-2)

=k*6198.34 j/sec

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