When 235 U fissions, the fission products are not always the same and exactly tw

Question

When 235U fissions, the fission products are not always the same and exactly two neutrons are not always released. An example of one fission reaction is

1) What is the energy released in this fission?

Q = 180.76 MeV

Q = 173.29

3) Lets assume that these are the only two fission reactions that take place (they are not), and that they take place at equal rates so the amount of energy released in every fission of 235U is the average of these two. How many gallons of gas would have to be burned to release the same amount of energy released when one kilogram of 235U undergoes fission? (A gallon of gasoline releases about 2.0X108J of energy when burned.)

Ngallons = ???? NEED HELP WITH THIS QUESTION - NOT SURE WHAT TO OR HOW TO GET INTO GALLONS!

You may want to use the following table of atomic masses: (GOES WITH QUESTION 1)

Table of masses 141Ba 140.9144 u 144Ba 143.9229 u 139Te 138.9347 u 141Cs 140.9196 u 90Kr 89.91952 u 91Kr 90.92344 u 92Kr 91.92615 u 94Zr 93.90632 u 93Rb 92.92157 u 235U 235.0439 u p 1.00728 u n 1.00867 u

Explanation / Answer

1.

Q= (235.0439 u - 143.9229 u - 89.91952 u-2*1.00867 u ) c^2

Q= 0.1928 u c^2 = 0.1928*931.5 MeV

Q=179.60 MeV

2.

Q=(235.0439 u 138.9347 u- 93.90632 u-2×1.00867 u) C^2

Q=(235.0439 138.9347 - 93.90632-2×1.00867)×931.5 MeV

Q=172.83 MeV

3.

Number of atoms in 1 Kg of Uranium:

X=(1000/235)*6.023*10^23

X=25.629*10^23 atoms

Energy released by 1kg of uranium= (25.629×10^23×179.60÷2)+(25.629×10^23×172.83÷2)

E=4.516*10^26 MeV

E=4.516*10^26×10^6*1.6*10^-19

E=7.225*10^13 J

Number of gallons N=7.225*10^13÷2.0*10^8

N=3.612*10^5 gallons

1 Kg of Uranium is equal to 0.2642 gallons

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