A) Anna walks 61 m due north, 76 m due east, and then 89 m due south. What is th

Question

A) Anna walks 61 m due north, 76 m due east, and then 89 m due south. What is the direction (angle in degrees) of her net displacement as measured from the x axis where counterclockwise is the positive direction?

B) An object is thrown vertically upward with a speed of 14.66mph. How much time from launch will it take to reach the bottom of a well 5.64 m deep?

C)If vector A has an x-component of 2.89 m and a y-component of 4.08 m, and vector B has an x-component of 3.26 m and a y-component of 3.62 m, then what is the magnitude of the vector Egiven by the vector sum of 3A + 5B?

D)A predatory fish can accelerate from rest to 4.36m/s in 0.16s. What is the acceleration of the fish?

Just need answers, wanna compare to mine. Much appreciated!!!

Explanation / Answer

here,

Anna walks 61 m due north , d1 = 61 j m

then 76 m due east , d2 = 76 i m

then 89 m due south , d3 = - 89 j m

her net displacement , dnet = d1 + d2 + d3

dnet = 61 j + 76 i - 89 j

dnet = 76 i m - 28 j m

the direction of her net displacement , theta = tan-1(- 28/76)

theta = - 20.22 degree

the direction of her net displacement is - 20.22 degree

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