CAN SOMEONE PLEASE HELP ANSWER THIS! I GOT A BUT CANT GET PART B AND THIS IS DUE

Question

CAN SOMEONE PLEASE HELP ANSWER THIS! I GOT A BUT CANT GET PART B AND THIS IS DUE IN AN HOUR PLEASE! HELP WILL BE GREATLY APPRECIATED. PART A WAS .900 J.

A nuclear power plant operates between a high-temperature heat reservoir at 540 C and a low-temperature stream at 25 C.

part a

Determine the maximum possible efficiency of this thermodynamic engine.

part b

Determine the heating rate (J/s) from the high-temperature heat reservoir to the power plant so that it produces 1000 MW of power (work/time).

Explanation / Answer

Here ,

part A)

Tc = 25 C

Tc = 298 K

Th = 540 C

Tc = 813 K

maximum efficiency = 1 - Tc/Th

maximum efficiency = 1 - 298/813

maximum efficiency = 0.633

the maximum possible efficiency of this thermodynamic engine is 0.633

part B)

power produced , P = 1000 MW

let the heat from the high temperature is Qh

as efficiency = W/Qg

0.633 = 1000/Qh

Qh = 1578.6 MW

Qh = 1.579 *10^9 J/s

the heating rate (J/s) from the high-temperature heat reservoir to the power plant is 1.579 *10^9 J/s

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