F = Gm1m2/d2 (Newton’s Law of Gravity, the gravitational attraction between two
ID: 1403619 • Letter: F
Question
F = Gm1m2/d2 (Newton’s Law of Gravity, the gravitational attraction between two objects)
it gets 15 times stronger
it quadruples
it gets 4 times weaker
nothing
F = keq1q2/d2 (Coulomb’s Law for the electrical force between two charged objects)
If the electric charge on one of the objects increases what happens to the electrical force between the two charges?
it stays the same
it strengthens
it weakens
F = keq1q2/d2 (Coulomb’s Law for the electrical force between two charged objects)
Suppose we have two charged particles. What happens to the electric force between them if we double the charge on one of the particles, triple the charge on the other and move the charges half as far apart?
it increases by a factor of 12
it increases by a factorof 6
it increases by a factor of 4
it increases by a factor of 24
F = keq1q2/d2 (Coulomb’s Law for the electrical force between two charged objects)
Which of the following is irrelevant concerning the electrical force between two objects?
the distance between objects
none of the other answers is correct
the mass of either object
the electric charge on either object
r = kaTA/L (equation for heat conduction through a rod)
In a circumstance where this equation is valid, which of the following does not affect the rate of heat conduction through a rod?
the cross sectional area of the rod
the temperature difference across the rod
the length of the rod
the velocity of the rod
Explanation / Answer
you have asked multiple question .I can only answer three as per guidelines.Please raise different questions for other one's.
in first case
F = Gm1m2/d^2
so F=G*4m1*4m2/16 d^2
F=Gm1m2/d^2--remians same
b) F = keq1q2/d2
since electric charge is directly propotional to force
so if electric charge increase the force will increase too,
so it strengthens
c) F = keq1q2/d2
here q1 and q2 are charge
d is distance so here the mass is irrelevant
so answer is the mass of either object is irrelevant
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