A Volkswagen bug is moving to the right with a speed of 20 m/s. A large SUV is m

Question

A Volkswagen bug is moving to the right with a speed of 20 m/s. A large SUV is moving to the left at a speed of 20 m/s. The SUV has a mass three times that of the small car. They have an totally inelastic head-on collision in an intersection. There are two passengers in each vehicle, one seat-belted and the other not seat-belted. All the passengers weigh the same. The non-seat-belted passengers both collide with the dashboard of their respective cars. Use the following codes to refer to each of the passengers: SB = SUV, belted SN = SUV, non-belted VB = Volkswagen, belted VN = Volkswagen, non-belted

1. Rank the magnitude of the impulse experienced by the four passengers in this collision from smallest to largest. If two impulses are equal, then show an equals sign between them.

a. SB = SN < VB = VN

b. VB = VN < SB = SN

c. SB < SN < VB < VN

d. SB < VB < SN < VN

2. Rank the magnitude of the forces experienced by the four passengers in this collision, from smallest to largest. If two forces are equal, then show an equals sign between them.

a. SB = SN < VB = VN

b. VB = VN < SB = SN

c. SB < SN < VB < VN

d. SB < VB < SN < VN

Explanation / Answer

momentum before collision = momentum after collision

m*u1-(3*m*u2) = (m+3m)*v

u1 = u2 = 20 m/s

-2*m*20 = 4*m*v

v = -10 m/s

v is the common velocity of the car and SUV after the collision

Since impulse is J = chnage in momentum = m*(v-u)

u is the initial velocity which is same for car and SUV

non belted paasengers are collide with dashboards with a force which is called as a internal force

Due to internal forces the momentum doesnot changes then impulse is also same experienced byseatbelted and non seat belated

Since SUV has mass 3 times greater than massof the car

so the correct option is a) SB=SN<VB=VN

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2) the force and impulse are in the same oprder of rank

Since impulse j = F*dt

then correct option is a) SB=SN<VB=VN

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