Exercise 11.30 A vertical solid steel post of diameter d = 21 cmand length L = 2
ID: 1403946 • Letter: E
Question
Exercise 11.30
A vertical solid steel post of diameter d = 21 cmand length L = 2.80 m is required to support a load of mass m = 8000 kg . You can ignore the weight of the post. Take free fall acceleration to beg=9.8m/s2.
Part B
What is the strain in the post?
Express your answer using two significant figures.
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Part C
What is the change in the post's length when the load is applied?
Express your answer using two significant figures.
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LL =Explanation / Answer
a)
youngs modulus of steel is = 200 * 10^9 N/m^2
E = stress/strain
200 * 10^9 = F / A * strain
200 * 10^9 = 8000 * 9.8 / ( 3.14 * 0.105^2) * strain
strain = (8000 * 9.8 ) / (3.14 * 0.105^2 * 200 * 10^9 )
strain = 1.13 * 10^-5
b)
by using the same formula
E = stress / strain
E = F * L / A * dL
200 * 10^9 = 8000 * 9.8 * 2.8 / ( 3.14 * 0.105^2 * dL)
dL = (8000 * 9.8 * 2.8 ) / ( 3.14 * 0.105^2 * 200 * 10^9)
dL = 3.1 * 10^-5 m
the change in the length is 3.1 * 10^-5 m
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