Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

Exercise 11.31 The bulk modulus for bone is 15.0 GPa . Part A If a diver-in-trai

ID: 1473736 • Letter: E

Question

Exercise 11.31

The bulk modulus for bone is 15.0 GPa .

Part A

If a diver-in-training is put into a pressurized suit, by how much would the pressure have to be raised (in atmospheres) above atmospheric pressure to compress her bones by 0.120 % of their original volume?

SubmitMy AnswersGive Up

Part B

Given that the pressure in the ocean increases by 1.0×104Pa for every meter of depth below the surface, how deep would this diver have to go for her bones to compress by 0.120 % ?

SubmitMy AnswersGive Up

Part C

Does it seem that bone compression is a problem she needs to be concerned with when diving?

Exercise 11.31

The bulk modulus for bone is 15.0 GPa .

Part A

If a diver-in-training is put into a pressurized suit, by how much would the pressure have to be raised (in atmospheres) above atmospheric pressure to compress her bones by 0.120 % of their original volume?

P = atmospheres

SubmitMy AnswersGive Up

Part B

Given that the pressure in the ocean increases by 1.0×104Pa for every meter of depth below the surface, how deep would this diver have to go for her bones to compress by 0.120 % ?

d =   m  

SubmitMy AnswersGive Up

Part C

Does it seem that bone compression is a problem she needs to be concerned with when diving?

Explanation / Answer

Here ,

Bulk modulus , B = 15 *10^9 Pa

let the pressre is P

as B = stress/strain

15 *10^9 = P /(0.12 *10^-2)

P = 1.8 *10^7 Pa

P = 1.8 *10^7 /(1.01 *10^5) atm

P = 178.2 atm

the pressure needed is 178.2 atm

-------------------------


B)

let the depth is d

Pf = Pi + 1.0 *10^4 * d

1.8 *10^7 = 1.01 *10^5 + 1.0 *10^4 * d

d = 1789.9 m

the depth of water is 1789.9 m
-------------------------------

C)

NO , this is a very small compression ,

and will not make much difference