A. In this problem, the calculating has been done for you. The questions ask abo

Question

A. In this problem, the calculating has been done for you. The questions ask about the reasoning involved in the calculations. Problem: A sample of liquid has a mass of 1.04 kg and a volume of 1300 ml. If the mass of the sample is to be increased by 70 g by adding more of the same kind of liquid, what volume of liquid must be added? Solution: (I) 1040 / 1300 = 0.80 (2) 70 / 0.80 = 88 I. Give an interpretation (not a name) for the number 0.80 in this context. 2. Give an interpretation (not a name) for the number 88 in this context. B. Here is another problem like the one above. Problem: Two blocks of metal have the same mass. The first block has a volume of 827 cm^3 and a density of 4.50 g/cm^3. The second block has a volume of 193 cm^3. What is the density of the second block? Solution: (I) 4.50 x 827 = 3720 (2) 3720 / 193 = 19.3 1. Give an interpretation (not a name) for the number 3720 in this context. 2. Give an interpretation (not a name) for the number 19.3 in this context.

Explanation / Answer

a) in the first step 1040 is the mass in grams.

1300 is volume in ml.
hence 0.8 is density in gram/ml.

2. 70 is extra mass to be added in grams.

0.80 is density in grams/ml.

then 70/0.80=88 is the volume of the liquid to be added in ml.

B.
1.

4.50 is density in gram/cm^3
827 is volume in cm^3

hence their multiplication 3720 is mass in grams.

2.

3720 is mass in grams.

193 is volume of second block in cm^3.
then their division will give density of second block in gram/cm^3

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