A stone is thrown 50m vertical cliff at an angle 30 degrees above the horizontal

Question

A stone is thrown 50m vertical cliff at an angle 30 degrees above the horizontal and with initial speed 25 m/s; some time later the stone strikes a vertical wall which is 72m away as measured horizontally from base of vertical cliff. A. Find total time stone was in air B. where does stone hit wall? C. Find magnitude and direction of stone before it strikes wall A stone is thrown 50m vertical cliff at an angle 30 degrees above the horizontal and with initial speed 25 m/s; some time later the stone strikes a vertical wall which is 72m away as measured horizontally from base of vertical cliff. A. Find total time stone was in air B. where does stone hit wall? C. Find magnitude and direction of stone before it strikes wall A. Find total time stone was in air B. where does stone hit wall? C. Find magnitude and direction of stone before it strikes wall

Explanation / Answer

along horizantal

initial velocity = vox = vo*cos30 = 25*cos30 = 21.65 m/s

ax = 0

distance travelled before srtiking X = 72 m

along vertical

voy = vo*sin30 = 12.5 m/s

ay = -9.8 m/s^2

part(A)

along horizantal

X =vox*T

T = X/vox = 72/21.65

T = 3.33 s <<<<-----answer

++++++++++++++++

part(B)

along vertical

y = voy*T + 0.5*g*T^2

y = (12.5*3.33)-(0.5*9.8*3.3^2)

y = -11.74 m

the stone strikes the wall at a point 11.46 below the cliff

++++++++++++

C)

vy = voy + gT

vy = (12.5)-(9.8*3.33)

vy = -20.134 m/s

magnitude = sqrt(vox^2+vy^2)

v = 29.56 m/s

direction = tan-1(vy/vx) = 49.92 below the horizantal

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