can someone help answer 7 and 8 The figure below shows a cylindrical Gaussian su

Question

can someone help answer 7 and 8 The figure below shows a cylindrical Gaussian surface enclosing a segment of a long charged wire whose linear charge density is lambda. Consider using a spherical Gaussian surface to enclose the same segment of the wire. 1. Which surface, cylindrical or spherical, has the greater electric flux through it? Justify your answer. 2. Which surface, cylindrical or spherical, is more appropriate for calculating the electric flux? Justify your answer. Consider the cylindrical Gaussian surface, with radius r and length L. 3. What Is the angle between the electric field lines and the area vectors of the flat ends of the cylinder? 4. What Is the electric flux through each of the flat ends of the cylindrical surface? 5. What is the angle between the electric field lines and the area vectors of the curved surface of the cylinder? 6. What is the electric flux through the curved surface of the cylinder? 7. Write the electric charge enclosed by the cylinder in terms of lambda and L. 8, Use Gauss's law to find and expression for the electric field at a distance r from the center of the wire and the line charge density lambda

Explanation / Answer

#7)

electric charge q = L*lambda

#8)

from gauss law = total electric flux = q/eo = lambda*L/eo >>>>(1)

flux = E*A

A = surface area of cylinder

A = 2*pi*r*L

total flux = E*2*pi*r*L...............(2)

therfore from 1 & 2

E*2*pi*r*L = lambda*L/eo

E = lambda/(2*pi*eo*r)      <<<<<<<<<<<<----answer

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