The studio apparatus is shown in the drawing below (Figure 1) . A string connect

Question

The studio apparatus is shown in the drawing below (Figure 1) . A string connects the two-body system, which is defined as the cart and force probe together (m1) and the falling mass (m2). The cart and force probe are held in place initially; when released, m2accelerates downward and the cart and force probe accelerate along the track to the right. The force probe first measures the tension in the string at rest and then as it accelerates.Suggestion: draw free body diagrams as an aid to answering the questions.

Typical values for m1 and m2 are on the order of 650 g and 75 g, respectively. Calculate the value of the acceleration in units of g for these values of mass.

Calculate the magnitude of the percentage drop in Trest when the system accelerates, for m1 and m2 of 1000 g and 100 g, respectively.

Before release, if the system was held at rest by fixing m2 in place instead of fixing m1 in place, what would be the tension in the string?

Explanation / Answer

Taking m1, string and m2 as system, only external force acting on this system = m2*g
a = Net force / Net mass
=m2g / (m1+m2)
= 0.075 Kg * 9.8 m/s^2 / (0.65 Kg +0.075 Kg)
= 1.014 m/s^2

When everything is at rest : T rest = m2*g = 0.1 Kg * 9.8 m/s^2 = 0.98 N
When they are free to move,
a = m2g / (m1+m2)
= 0.1*9.8 / (0.1+1)
= 0.891 m/s^2
T = m2(g-a)
= 0.1* (9.8-0.891)
= 0.89 N
drop in tension = 0.98 - 0.89 = 0.09 N
percentage drop = 0.09 *100/ 0.98 = 9.18 %

If we fix me, string will become loose and Tension will be 0

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.