When water was passed through a continuous flow calorimeter the rise in temperat

Question

When water was passed through a continuous flow calorimeter the rise in temperature was from 16.0 to 20.0°C, the mass of water flowing was 100 g in 1 minute, the potential difference across the heating coil was 20.0 V and the current was 1.50 A. Another liquid at 16.0 °C was then passed through the calorimeter and to get the same change in temperature the potential difference as changed to 13.0 V, the current to 1.20 A and the rate of flow to 120 g in 1 minute.

a. What is the specific heat capacity of the liquid?

b. State two advantages of the continuous flow method of calorimetry.

Explanation / Answer

C =(power P)/(flowrate Q*T)
Cliquid/Cwater = (P/(QT)liquid)/(P/QTwater) = (13*1.2/(120*4))/(20*1.5/(100*4))
Cliquid = 4200J/kg-K*(13*1.2/(120*4))/(20*1.5/(100*4)) = 1820 J/kg-K

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