A parallel-plate capacitor with plate separation of 1.0 cm has square plates, ea

Question

A parallel-plate capacitor with plate separation of 1.0 cm has square plates, each with an area of 6.0 times 10^-2 m^2. What is the capacitance of this capacitor if a dielectric material with a dielectric constant of 2.4 is placed between the plates, completely filling them? (epsilon_0=8.85 times 10^-12 C_2/N.m^2) A parallel-plate capacitor has a capacitance of 10 mF and is charged with a 20-V power supply. The power supply is then removed and a dielectric material of dielectric constant 4.0 is used to fill the space between the plates. What is the voltage now across the capacitor?

Explanation / Answer

Q8.

C = ke0A/d

= 2.4(8.85*10^-12)*0.06 / 0.01

epsilon 0 = 8.85*10^-12 C^2/N*m^2

= 1.2744 * 10^-10 F

or 1.3 * 10^-10 F

Please post other question separately.

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