A small ball of mass m = 2.8 kg and charge 30 muC is initially 3 m from a ball f

Question

A small ball of mass m = 2.8 kg and charge 30 muC is initially 3 m from a ball fixed in space and having a charge of -50 muC. The moving ball has an initial velocity away from the other of V_0 = 1.5 m/s What is the electric potential due to the -50 muC charge at a distance of 3 m? What is the initial potential energy of the 30 mu C charged ball? What is the initial kinetic energy of the 30 mu C charged ball? What is the farthest the 30 mu C charged ball will get from the other ball before being pulled back by the electric attraction?

Explanation / Answer

the mass of small ball m=2.8 kg

initial velocity Vo=1.5 m/s

charge Q2=30µC

charge Q1=-50µC

(a) ans

the elecric field of charge Q2>E=K Q2/r^2

=9*10^9 *30*10^-6/3^2

=30*10^3 N/m

(b) ans

the electric potential of charge Q2=> V=K.Q2/r

=9*10^9*30*10^-6/3

=90*10^3 N/c.m

(c) ans

the potential energy of charged ball U=K Q1Q2/r

=-9*10^9*30*50*10^-12/3

=-4500*10^-3=-4.5 J

(d) ans

the initial kinetic energy of ball of 30µC => K.E=1/2 mVo^2

=1/2*2.8*(1.5)^2=3.15 J

(e) ans

the farthest distance to meet is denoted X

the farthest distance X=d/(Q2/Q1)^½ +1

=3/(30/-50) -1

=1.9 m

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