Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

WAH Phy X C https:// 13617674 Comment: Need Help? Read it 6. C+ 013 points I Pre

ID: 1409577 • Letter: W

Question

WAH Phy X C https:// 13617674 Comment: Need Help? Read it 6. C+ 013 points I Previous Answers SerPSE9 24. P.053.soln My Notes A very large conducting plate lying in the xy plane carries a charge per unit area of 30. A second such plate located at z 6.00 cm and oriented parallel to the xy plane carries a charge per unit area of o. Find the electric field for the following. (Take upward to be in the positive z-direction (a) z 0 The correct answer is not zero. o/Eo (b) 0 z 6.00 cm Your response differs from the correct answer by more than 10%. Double check your calculations. O/Eo (c) z 6.00 cm The correct answer is not zero. o/Eo Need Help? Read it Submit Answer Save Progress Practice Another Version 7. C+ 8/8 points I Previous Answers SerPSE9 24.P.054. My Notes A solid, insulating sphere of radius a has a uniform charge density throughout its volume and a total charge of Q. Concentric with this sphere is a uncharged, conducting hollow sphere whose inner and outer radii are b and c as shown in the figure below. We wish to understand completely the charges and electric fields at a locations. Use the following as necessary: Q, Eo, a, b, c and r. Do not substitute numerical values use variables only.) Insulator Conductor

Explanation / Answer

Here ,

for sigm1 = 3 * sigma

sigma2 = -8 * sigma

a) for z < 0

electric field = - (sigma1 + sigm2)/(2 * epsilon_0)

electric field = - (3 * sigma - 8 *sigm)/(2 * epsilon_0)

electric field = 5 * sigma/(2 * epsilon_0)

b) for 0 < z < 6 cm

electric field = - (sigma1 - sigm2)/(2 * epsilon_0)

electric field = - (3 * sigma + 8 *sigm)/(2 * epsilon_0)

electric field = 11 * sigma/(2 * epsilon_0)

the electric field is 11 * sigma/(2 * epsilon_0)

c)

z > 6 cm

electric field = (sigma1 + sigm2)/(2 * epsilon_0)

electric field = (3 * sigma - 8 *sigm)/(2 * epsilon_0)

electric field = -5 * sigma/(2 * epsilon_0)