A blue car travelling at constant velocity of 24.0 m/s is 350 m behind a bus tra

Question

A blue car travelling at constant velocity of 24.0 m/s is 350 m behind a bus travelling at 36 km/h. How long will it take the blue car to reach the bus? Calling x=0 the initial position of the blue car, how far from the initial position from the initial position does the blue car meet the bus?

A) time = 17.5 s, distance = 1200 m                      B) ) time = 25 s, distance = 1200 m                      

C) time = 87.5 s, distance = 600 m                        D) time = 25 s, distance = 600 m

Explanation / Answer

Vc = 24 m/sec

Vb = 36 km/h = 10 m/sec

lets assume bus travels "x" m, when car catches Bus

then distance traveled by bus = x m

distance traveled by car = (350 + x) m

time for car

tc = (350 + x)/24

time for bus will be

tb = x/10

tc = tb

(350 + x)/24 = x/10

3500 + 10x = 24x

14x = 3500

x = 3500/14 = 250 m

distance traveled by car = 350 + 250 = 600 m

time for car will be

tb = (350 + 250)/24 = 600/24

tb = 25 sec

Correct option is D

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.