A blue car with mass m c = 401 kg is moving east with a speed of v c = 21 m/s an

Question

A blue car with mass mc = 401 kg is moving east with a speed of vc = 21 m/s and collides with a purple truck with mass mt = 1229 kg that is moving south with a speed of vt = 13 m/s . The two collide and lock together after the collision. try {try} {big}

1. What is the magnitude of the initial momentum of the car? _____ kg-m/s

2. What is the magnitude of the initial momentum of the truck? ____ kg-m/s

3. What is the angle that the car-truck combination travel after the collision? (give your answer as an angle South of East)

4. What is the magnitude of the momentum of the car-truck combination immediately after the collision? ___ kg-m/s

5. What is the speed of the car-truck combination immediately after the collision? _____m/s

6. Compare the initial and final kinetic energy of the total system before and after the collision:

a) KEi = KEf

b) KEi > KEf

c) KEi < KEf

Explanation / Answer

1. momentum = mass*velocity
momentum = (401kg)*(21m/s) = 8421kg-m/s
2. momentum = mass*velocity
momentum = (1229kg)*(13m/s) = 15977 kg-m/s
3. angle after collision = tan^-1(-momentum truck/momentum car)
angle after collision = tan^-1(-15977/8421) = -62.21° = 62.21° south of east
4. total momentum = Pc^2 +Pt^2)
total momentum = (8421^2)+(15977^2)) = 18060.4 kg m/s
5. final velocity = (total momentum)/(total mass) = (18060.4/1630) = 11.08m/s

(6)b) KEi > KEf. this is because the collision is inelastic .so some kinetic energy is lost

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