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Thermodynamics Focus on Concepts, Question 01 Focus on Concepts, Question 02 Foc

ID: 1410589 • Letter: T

Question

Thermodynamics Focus on Concepts, Question 01 Focus on Concepts, Question 02 Focus on Concepts, Question 03 Focus on Concepts, Question 04 Focus on Concepts, Question 05 Focus on Concepts, Question 06 Chapter 15, Problem 004 GO Chapter 15, Problem 005 GO Chapter 15, Problem 007 Chapter 15, Problem 008 Review Score Review Results by Study Objective While running, 6.2 times 10^5 J of work is done by a jogger and 4.1 times 10^5 J of heat is lost by the jogger. What is the change Delta U in the jogger's internal energy? Be sure to include the correct algebraic sign. Delta U = Number Units the tolerance is +/-2 percent

Explanation / Answer

from the law of thermodYNAMICS

dU = dQ + dW


so internal energy chnage dU = 6.2 *10^5 + 4.1 *10^5

dU = -10.3 *10^5 Joules

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