A softball is hit over a third baseman\'s head with some speed v0 at an angle ab

Question

A softball is hit over a third baseman's head with some speed v0 at an angle above the horizontal. Immediately after the ball is hit, the third baseman turns around and begins to run at a constant velocity V=7.00m/s. He catches the ball t=2.00s later at the same height at which it left the bat. The third baseman was originally standing L=18.0m from the location at which the ball was hit. A.Find v0. Use g=9.81m/s2 for the magnitude of the acceleration due to gravity. B. Find the angle in degrees.

Explanation / Answer

distance travelled by the third batsman = speed * time

distance travelled by the third batsman = 7 * 2

distance travelled by the third batsman = 14 m

total horizontal distance travelled by the ball = 18 + 14

total horizontal distance travelled by the ball = 32 m

horizontal distance of the projectile = v^2 * sin(2 * theta) / g

v^2 * sin(2 * theta) / 9.8 = 32

time of flight = 2 * v * sin(theta) / g

2 * v * sin(theta) / 9.8 = 2

on solving we'll get

v = 18.7627 m/s

theta = 31.49 degree

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