A cannonball is fired horizontally from the top of a cliff. The cannon is at hei

Question

A cannonball is fired horizontally from the top of a cliff. The cannon is at height H = 70.0m above ground level, and the ball is fired with initial horizontal speed v0. Assume acceleration due to gravity to be g = 9.80m/s2 . Assume that the cannon is fired at time t=0 and that the cannonball hits the ground at time tg. Given that the projectile lands at a distance D = 130 m from the cliff and its initial speed is 32.2 m/s. What is the y position of the cannonball when it is at distance D/2 from the hill?

Explanation / Answer

use the kinematic equation H = 0.5 gt^2

at time t = tg

tg = sqrt(2H/g)

speed Vox = D/tg

Vox = D/sqrt(2(H-y)/g

32.2 = 130/(sqrt(2*(y)/9.8))

y = 80 m

actual height = 80-70 = 10 m

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