Two people, one of mass 90 kg and the other of mass 61 kg , sit in a rowboat of

Question

Two people, one of mass 90 kg and the other of mass 61 kg , sit in a rowboat of mass 63 kg . With the boat initially at rest, the two people, who have been sitting at opposite ends of the boat 3.4 m apart from each other, now exchange seats. Two people, one of mass 90 kg and the other of mass 61 kg , sit in a rowboat of mass 63 kg . With the boat initially at rest, the two people, who have been sitting at opposite ends of the boat 3.4 m apart from each other, now exchange seats. How far will the boat move?

Explanation / Answer

here,

m1= 90 kg

m2 = 61 kg

mass of boat ,m = 63 kg

length of boat , l = 3.4 m

taking the left ened of the boat to be origin

initial centre of mass , x = ( 90 * 0 + 61 * l + 63 * l/2) /( m1 + m2 + m)

x = ( 61 * 3.4 + 63 * 3.4/2)/( 90 + 61 + 63)

x = 1.47 m

final centre of mass , x1 = ( m2 * 0 + m1 * l + m * l/2) /( m1 + m2 + m)

x1 = ( 0 + 90 * 3.4 + 63 * 3.4/2) /( 90 + 61 + 63)

x1 = 1.93 m

the distance boat moved , d = x1 - x = 1.93 - 1.47 = 0.46 m

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