Common transparent tape becomes charged when pulled from a dispenser. If one pie
ID: 1413327 • Letter: C
Question
Common transparent tape becomes charged when pulled from a dispenser. If one piece is placed above another, the repulsive force can be great enough to support the top piece's weight. Assuming equal point charges (only an approximation), calculate the magnitude of the charge if electrostatic force is great enough to support the weight of a 7.00 mg piece of tape held 0.60 cmabove another. (The magnitude of this charge is consistent with what is typical of static electricity.)Common transparent tape becomes charged when pulled from a dispenser. If one piece is placed above another, the repulsive force can be great enough to support the top piece's weight. Assuming equal point charges (only an approximation), calculate the magnitude of the charge if electrostatic force is great enough to support the weight of a 7.00 mg piece of tape held 0.60 cmabove another. (The magnitude of this charge is consistent with what is typical of static electricity.)
Common transparent tape becomes charged when pulled from a dispenser. If one piece is placed above another, the repulsive force can be great enough to support the top piece's weight. Assuming equal point charges (only an approximation), calculate the magnitude of the charge if electrostatic force is great enough to support the weight of a 7.00 mg piece of tape held 0.60 cmabove another. (The magnitude of this charge is consistent with what is typical of static electricity.)
Explanation / Answer
mass m=7 mg=7*10^-6 kg
distance r=0.60 cm=60*10^-4 m
this concept belongs to electrostatices
according to the coloumbs inversquare law
Fe=9*10^9*Q^2/r^2...........................(1)
but =>F=mg.....
=7*10^-6*10=7*10^-5 N............................(2)
now we combained the equation 1&2
7*10^-5 =9*10^9*Q^2/(6*10^-3)^2
7*10^-5*36*10^-6=9*10^9*Q^2
28*10^-20=Q^2
the magnitude of the charge Q=5.3*10^-10 C
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