Q12 please help me answering this question, step by step 12 -13 points My Notes

Question

Q12 please help me answering this question, step by step

12 -13 points My Notes Ask Your Teacher [HRW 57-40Pabc] A 250 g block is dropped onto a vertical spring with spring constant k 2.42 N/cm (Fig. 7-41). The block becomes attached to the spring, and the spring compresses 11.0 cm before momentarily stopping Figure 7-41. While the spring is being compressed, what work is done on the block (a) by its weight and (b) by the spring force? (c) What is the speed of the block just before it hits the spring? (Assume that friction is negligible.) m/s

Explanation / Answer

a)

here

the work done by the weight is

W1 = m * g * d

W1 = 0.25 * 9.8 * 0.11

W1 = 0.2695 J

b)

work done by the spring is

W2 = - 0.5 * k * d^2

W2 = 0.5 * 242 * 0.11^2

W2 = - 1.46 J

c)

by using work kinetic energy theorem

delta KE = 0 - 0.5 * m * vi^2

vi = sqrt ( -2 * (W1 + W2 ) / m )

vi = sqrt ( -2 * ( 0.2695 - 1.46 ) / 0.25 )

vi = 3.08 m/s

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