A Bar Suspended by Two Vertical Strings The figure (Figure 1) shows a model of a

Question

A Bar Suspended by Two Vertical Strings The figure (Figure 1) shows a model of a crane that may be mounted on a truck. A rigid uniform horizontal bar of mass m_1 = 90.0 kg and length L = 5.30 m is supported by two vertical massless strings. String A is attached at a distance d = 2.00 m from the left end of the bar and is connected to the top plate. String B is attached to the left end of the bar and is connected to the floor. An object of mass m_2 = 3000 kg is supported by the crane at a distance x = 5.10 m from the left end of the bar. Find T_A, the tension in string A. Express your answer in newtons using three significant figures. Find T_B, the magnitude of the tension in string B. Express your answer in newtons using three significant figures.

Explanation / Answer

As bar is in rotational equilibrium,taking torque at left end

Torque due to T(B) =0

Torque due to T(A) =T(A)*2.0 counterclockwise

Torque due to weight of bar = 90*9.81*2.65=2339.685 N clockwise

Torque due to weight of object =3000*9.81*5.1=150093 N clockwise

counterclockwise torque =clockwise torque

T(A)*2.0 =152432.685

T(A) =76216.3425 N

T(B) + m1g +m2g =T(A)

T(B)=76216.3425 -3090*9.81

T(B) =45903.4425 N

(1) T(A) the tension in string A.is 76216.3425 N

(2) T(B) the magnitude of the tension in string B is 45903.4425 N

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.