A submarine prepares to drive into the ocean of a strange planet. The surface gr

Question

A submarine prepares to drive into the ocean of a strange planet. The surface gravity of this planet is s. made of various minerals and liquids such that its density is 1120 kg/m^3 has a surface area of 280 square meters and a the sea level air pressure on this planet is the same as Earth's. If the water at the depth of 4000 m was moving with a velocity of 12 m/s then what would the water pressure be? Not including the inwards crushing force what, is the net force on the submarine at a depth of 40(H) m? What is the inwards crushing force on the outer hull of the submarine? Water in a pipe with radius of 2.2 in flows with a velocity of 5.0 m/s. The water then flows into a pipe with a radius of 1.4 m. What will the velocity of water be in the 1.4 m pipe?

Explanation / Answer

(a)

Pressure @ the depth of 4000 m.

P = Patm + rho*g*h

= 1.01325*10^5 + 1120*9.81*4000

P =4.405*10^107 Pa

(c) Inward crushing force,

F = P*A =4.405*10^107*280

   =1.233*10^10 N

(b)

Net force excluding, crushing force,

F =W - rho*V*g

= 1.1*10^8 - (1120*12000)*9.2

=-1364000 N

-ve sign shows, its a lift force.

Since submarine is moving with uniform velocity, using Newton's 1st law, there's no effect on it due to velocity.

(d)

Using continuity equation,

A1*v1 = A2*v2

pi*r1^2*v1 = pi*r2^2*v2

2.2^2 * 5 = 1.4*v2

v2 = 17.28 m/s (water velocity in 1.4m pipe)

Please comment if there's any doubt.

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