The two blocks in the figure above are connected by a mass less string. The surf

Question

The two blocks in the figure above are connected by a mass less string. The surface of the incline has a coefficient of kinetic friction of 0.05 and a coefficient of static friction of 0.3. The incline makes an angle of 35degree with the horizontal, and the block on the incline has a mass of 5.7 kg. Draw a well-labeled system schema for the problem. Calculate the greatest mass of the hanging block that would keep the system in static equilibrium. Increase the answer for the mass that you calculate in ) by 10% and calculate the acceleration for the system of masses.

Explanation / Answer

for static eqilibrium

m would be greatest when friction will be downward direction

mg = 5.7gsin35 + 0.3 *(5.7gcos35)

m = 4.67 kg answer

now if the m will increse by 10% them m' = 5.13 kg

now the system will not be in static eqi.

in this case the kinetic friction force will be in downward direction

so acceleration will be

ma = (m'g - 5.7gsin35 - 0.05 * 5.7gcos35 )

a = 3.12 m/s2

answer

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