The turbines in a hydroelectric plant are fed by water falling from a 60 m heigh

Question

The turbines in a hydroelectric plant are fed by water falling from a 60 m height. Assuming 90% efficiency for conversion of potential to electrical energy, and 5% loss of the resulting power in transmission, what is the mass flow rate of water required to power a 150 W light bulb? The turbines in a hydroelectric plant are fed by water falling from a 60 m height. Assuming 90% efficiency for conversion of potential to electrical energy, and 5% loss of the resulting power in transmission, what is the mass flow rate of water required to power a 150 W light bulb?

Explanation / Answer

dm/dt (gh) is the power generated

dm/dtgh*90%*95% = 150

dm/dtgh*0.90*0.95 = 150

dm/dt*9.8*60*0.90*0.95 = 150

dm/dt*9.8*6*0.90*0.95 = 15

dm/dt*9.8*6*0.90*0.95 = 15

dm/dt = 0.2984 kg/sec

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