Chrome File Edit View History Bookmarks People window Help 67%, Wed 6:11 PM E Mo

Question

Chrome File Edit View History Bookmarks People window Help 67%, Wed 6:11 PM E Morehead State University x www.saplinglearning.com/i x Physics question I Chegg X C ning.com, 2673388 Map Sapling Learning Po macmillan loamino Gra Four resistors are connected to a battery as shown in the figure. The current in the battery is l, the battery emf is E 6.30 V, and the resistor values are R1- R, R 2R, R3 4R, R4 3R. Find the voltages across De each resistor. Po Number R, 2R You You Number RI R ass You You Number an at t Number O e O H CO V

Explanation / Answer

This is just simple ohms law and the laws of parallel and series resistors.

R2 and R3 add to 6R
in parallel with R4, that is 3R•6R/(3R+6R) = 18R/9 = 2R
in series with R, total resistance is 3R

V = 6.30
I = V/R = V/3R
V1 = IR = (V/3R)R = V/3 = 2.1 V

V4 = V–(V/3) = (2/3)V
alternate, V4 = I(2R) = (V/3R)(2R) = (2/3)V = 4.2 V
V3 = V4(4R) / (4R+2R) = (2/3)V(4R)/(6R) = (2/3)(2/3)V = (4/9)V = 2.8 V
V2 = V4(2R) / (4R+2R) = (2/3)V(2R)/(6R) = (2/3)(1/3)V = (2/9)V = 1.4 V

Related Questions

Navigate

• Browse (All)
• Browse C
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.