An 86.0-m-long brass rod is struck at one end. A person at the other end hears t

Question

An 86.0-m-long brass rod is struck at one end. A person at the other end hears two sounds as a result of two longitudinal waves, one traveling in the metal rod and the other traveling in the air.

Part A

What is the time interval between the two sounds? Take the speed of sound in air to be 344 m/s .

An 86.0-m-long brass rod is struck at one end. A person at the other end hears two sounds as a result of two longitudinal waves, one traveling in the metal rod and the other traveling in the air.

Part A

What is the time interval between the two sounds? Take the speed of sound in air to be 344 m/s .

Explanation / Answer

Ebrass = 90 GPa

p = density of brass = 8.6*10^3 kg/m^3

Vrod = sqrt (E/p) = sqrt (90*10^9/(8.6*10^3))

Vrod = 3234.98 m/sec

distance = velocity*time

time to travel 86 m long brass rod

tb = d/Vrod = 86/3234.98

tb = 0.0266 sec

time to travel in air

tair = 80/344 = 0.232 sec

time difference will be

dt = 0.232 - 0.0266 = 0.2054 sec

dt = 0.2054 sec

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