Hello , i need the solution for this question with all the steps please help sin

Question

Hello , i need the solution for this question with all the steps please help since its my last attempt

Thanks in advance

Chapter 21, Problem 039 Your answer is partilly correct. Try again. Your answer is partially correct. Try again In the figure particle 1 of charge +5e is above a floor by distance d1 = 2.50 mm and particle 2 of charge +6e is on the floor, at distance d2 = 9.30 mm horizontally from particle 1, what is the x component of the electrostatic force on particle 2 due to particle 1? Number 17.18E-22 UnitsN the tolerance is +/-2% Question Attempts: 1 of 2 used SAVE FOR LATER SUBMIT ANSWER

Explanation / Answer

d21 = sqrt(d2^2 + d1^2) = sqrt(9.3^2 + 2.5^2)mm = 9.63mm = 0.00963m

F21 = k*q2*q1/d21^2 = 8.99*10^9*5*6*(1.6*10^-19)^2 / 0.00963^2

F21 = 7.44*10^-23 N

F21 is at angle arctan(2.2/4.8) below the horizontal = 24.6 degrees

So x component of F21 is 1.98*cos(24.6) * 10^-22 N = 1.80*10^-22 N

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