Exercise 3 - Collision Between Unequal Mass Balls This last part is similar to t

Question

Exercise 3 - Collision Between Unequal Mass Balls This last part is similar to the previous section except a plastic ball is used as the target. The mass of plastic ball is significantly less than the mass of the steel ball. Question What happens if the plastic ball is used as the projectile and the steel ball as the target? We first consider the case where the steel ball collides head on with the plastic ball. We assume that the collision is elastic, i.e., the initial and final kinetic energies are equal. In this case we have two equations Conservation of momentum m steel Vsteet + mplastic plassic plasie plas Conservation Of energy: 'ste-sted +3mplastic.plastic-2n'steelV.el+3mpl plastic 2 steel 2 where the prime represents the final velocities. These two equations simplify to plastic steel Note that the initial speed of the plastic, Vplastic-0. In part I, you found that the speed and momentum of the steel ball at the bottom of the ramp are 1.50 m/s and pi = mste-wel- 0.0488 kg·m/s respectively. By substituting Equation [9] into [7], the speeds of the steel and plastic balls after the collision can be determined. Simplifying gives plastc opla 10] The speed of the steel ball after collision is then steel plastic stee

Explanation / Answer

1)

Vplastic = 2x 0.0488 / 0.0182+0.0325

Vplastic = 1.925 m/sec

2)

Vsteel = 1.925-1.5 = 0.425 m/sec

3)

Rplastic balle = Vplastic x time

Rp = 44.21cm

4)

Rstell = Vsteel x time

Rs = 9.76 cm

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