After being kidnapped and placed in the trunk of a car, you discover you are abl

Question

After being kidnapped and placed in the trunk of a car, you discover you are able to pry open the trunk. Luckily your smart phone has a GPS system that receives signal when you open the trunk. The GPS tells you that you're moving 32.0mph in a direction 25 degrees N of E at a location 1.1. miles west of the police station. You then close the trunk so as not to be spotted. Five minutes later your ale another reading that tells you are now 1.9 miles north of the police station and are moving west at a speed of 12.0 mph.

What was your average velocity during this trip?

What was your average acceleration during this trip?

What is the distance and direction you would need to travel to return to the location of your first GPS reading if you jumped out of the car now?

Explanation / Answer

(a) Average velocity = displacement/time
Since it is hypotenuse of right triangle , therefore use pythogoras theorem.
Average velocity = (1.12+1.92)1/2 / (5/60) = 26.345 mph
(b) Average acceleration = 32-12 /(5/60) = 240 mph2
(c) distance = (1.12+1.92)1/2 = 2.195
direction
angle = tan-1(1.1/1.9) = 30.06 degree

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